925. Long Pressed Name(Solution || Leetcode easy || Java)

Palakkgoyal
2 min readNov 26, 2022

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Your friend is typing his name into a keyboard. Sometimes, when typing a character c, the key might get long pressed, and the character will be typed 1 or more times.

You examine the typed characters of the keyboard. Return True if it is possible that it was your friends name, with some characters (possibly none) being long pressed.

Example 1:

Input: name = "alex", typed = "aaleex"
Output: true
Explanation: 'a' and 'e' in 'alex' were long pressed.

Example 2:

Input: name = "saeed", typed = "ssaaedd"
Output: false
Explanation: 'e' must have been pressed twice, but it was not in the typed output.

Constraints:

  • 1 <= name.length, typed.length <= 1000
  • name and typed consist of only lowercase English letters.

SOLUTION:

class Solution {
public boolean isLongPressedName(String name, String typed) {
if(name.length() > typed.length()){
return false;
}

//initialize index to iterate over the strings
int i = 0;
int j = 0;

int nLen = name.length();
int tLen = typed.length();

while(i < nLen && j < tLen){
char ch = name.charAt(i);

if(name.charAt(i) != typed.charAt(j)){
return false;
}
i++; j++;

int nameCharLen = 0;
int typedCharLen = 0;

while(i < nLen && ch == name.charAt(i)){
i++;
nameCharLen++;
}

while(j < tLen && ch == typed.charAt(j)){
j++;
typedCharLen++;
}

if(nameCharLen > typedCharLen){
return false;
}
}

if(i == nLen && j == tLen){
return true;
}

return false;
}
}

Runtime: 1 ms, faster than 92.23% of Java online submissions for Long Pressed Name.

Memory Usage: 40.4 MB, less than 88.77% of Java online submissions for Long Pressed Name

Thank you for reading. If you have any queries then, please let me know in the comment section. I will surely be responsive toward it.

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Palakkgoyal
Palakkgoyal

Written by Palakkgoyal

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