557. Reverse Words in a String III(Solution || Leetcode easy || Java)

Given a string s, reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order.

Example 1:

Input: s = "Let's take LeetCode contest"
Output: "s'teL ekat edoCteeL tsetnoc"

Example 2:

Input: s = "God Ding"
Output: "doG gniD"

Constraints:

• 1 <= s.length <= 5 * 104
• s contains printable ASCII characters.
• s does not contain any leading or trailing spaces.
• There is at least one word in s.
• All the words in s are separated by a single space.

SOLUTION:

class Solution {
    public String reverseWords(String s) {
//Store words of s as elements of an array
        String[] temp = s.split(" ");

//Create a stringbuilder array to reverse the elements        
        StringBuilder[] sb = new StringBuilder[temp.length];


//Add elements from the string array to the stringbuilder array and 
//also reverse them        
       for(int i = 0; i < temp.length; i++){
           sb[i] = new StringBuilder(temp[i]);
           sb[i] = sb[i].reverse();
       }
   //Create a stringbuilder or you can also make a string to add 
  //the reversed elements     
        StringBuilder ans = new StringBuilder();
        
       for(int i = 0; i < temp.length; i++){
           if(i < temp.length - 1){
               ans.append(sb[i] + " ");
           }else{
               ans.append(sb[i]);
           }
       }
        
     
        
        return ans.toString();
    }
}

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