1528. Shuffle String(Solution || Leetcode easy || Java)
1 min readNov 22, 2022
You are given a string s
and an integer array indices
of the same length. The string s
will be shuffled such that the character at the ith
position moves to indices[i]
in the shuffled string.
Return the shuffled string.
Example 1:
Input: s = "codeleet", indices = [4,5,6,7,0,2,1,3]
Output: "leetcode"
Explanation: As shown, "codeleet" becomes "leetcode" after shuffling.
Example 2:
Input: s = "abc", indices = [0,1,2]
Output: "abc"
Explanation: After shuffling, each character remains in its position.
Constraints:
s.length == indices.length == n
1 <= n <= 100
s
consists of only lowercase English letters.0 <= indices[i] < n
- All values of
indices
are unique.
SOLUTION:
class Solution {
public String restoreString(String s, int[] indices) {
StringBuilder temp = new StringBuilder(s);
for(int i = 0; i < s.length(); i++){
String a = String.valueOf(s.charAt(i));
temp.replace(indices[i],indices[i] + 1,a);
}
return temp.toString();
}
}
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